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Samuel

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Can someone help solve this problem:

The average number of tractor (trucks) passing through a point is 1500 trucks per hour lane (tphl). The trucks travel at an average speed of 40mph. If the average truck length (bumper to bumper) is 70ft. What is the distance between the trucks?

 
Can someone help solve this problem:
The average number of tractor (trucks) passing through a point is 1500 trucks per hour lane (tphl). The trucks travel at an average speed of 40mph. If the average truck length (bumper to bumper) is 70ft. What is the distance between the trucks?
spacing=5280ft/mi / Dvpm/lane CERM eq. 73.11

Dvpm/lane = total cars / speed

Dvpm/lane= 1500 vpm/lane / 40 mph = 37.5 vpm/lane

Spacing = 5280 / 37.5 = 141 ft

141-70 (truck length) = 71 ft

What is the answer said?

 
Can someone help solve this problem:
The average number of tractor (trucks) passing through a point is 1500 trucks per hour lane (tphl). The trucks travel at an average speed of 40mph. If the average truck length (bumper to bumper) is 70ft. What is the distance between the trucks?
spacing=5280ft/mi / Dvpm/lane CERM eq. 73.11

Dvpm/lane = total cars / speed

Dvpm/lane= 1500 vpm/lane / 40 mph = 37.5 vpm/lane

Spacing = 5280 / 37.5 = 141 ft

141-70 (truck length) = 71 ft

What is the answer said?

I guess your are right, even from your method. Thanks

 
Can someone help solve this problem:
The average number of tractor (trucks) passing through a point is 1500 trucks per hour lane (tphl). The trucks travel at an average speed of 40mph. If the average truck length (bumper to bumper) is 70ft. What is the distance between the trucks?
spacing=5280ft/mi / Dvpm/lane CERM eq. 73.11

Dvpm/lane = total cars / speed

Dvpm/lane= 1500 vpm/lane / 40 mph = 37.5 vpm/lane

Spacing = 5280 / 37.5 = 141 ft

141-70 (truck length) = 71 ft

What is the answer said?

I guess your are right, even from your method. Thanks

Do you have another method, share with as. As more option we have, better

 
QUOTE (Samuel @ Aug 19 2010, 01:22 PM)

QUOTE (Tanya @ Aug 18 2010, 02:45 PM)

QUOTE (Samuel @ Aug 18 2010, 01:30 PM)

Can someone help solve this problem:

The average number of tractor (trucks) passing through a point is 1500 trucks per hour lane (tphl). The trucks travel at an average speed of 40mph. If the average truck length (bumper to bumper) is 70ft. What is the distance between the trucks?

spacing=5280ft/mi / Dvpm/lane CERM eq. 73.11

Dvpm/lane = total cars / speed

Dvpm/lane= 1500 vpm/lane / 40 mph = 37.5 vpm/lane

Spacing = 5280 / 37.5 = 141 ft

141-70 (truck length) = 71 ft

What is the answer said?

I guess your are right, even from your method. Thanks

Do you have another method, share with as. As more option we have, better
Assume it is a convoy travelling, length of convoy passing through a point in an hour must be 40 mi

(x distance between trucks)

(70+x)*1500 = 40*5280

x=70.8' say 71'

 
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