stlaggies
Active member
- Joined
- Jul 29, 2010
- Messages
- 34
- Reaction score
- 1
I seem to be stumped on this question.
Soil weighing 600.3 lbs is removed from a test pit. It takes 307.0 lbs of water to fill the test pit. A lab sample of this same soil weighing 105.5 grams is dried in an oven and its weight after drying is 97.2 grams. The max weight of the soil attained in the lab is 115.2lbs/ft^3 and the min is 102lb/ft^3. The SG of the soil solids is 2.7.
Find wet unit weight and dry unit weight:
How I'm trying to solve it: First i'm gonna find volume of solids and volume of water. I take the weight of solids to be .214 lbs and weight of water to be .018lbs. Using the formula I get .00127 for Vs and .000288 for Vw, which gives me something like 137 pcf for dry unit weight. Anyone help with where I made a mistake? My answer choices are 102, 112, 115, 122
Soil weighing 600.3 lbs is removed from a test pit. It takes 307.0 lbs of water to fill the test pit. A lab sample of this same soil weighing 105.5 grams is dried in an oven and its weight after drying is 97.2 grams. The max weight of the soil attained in the lab is 115.2lbs/ft^3 and the min is 102lb/ft^3. The SG of the soil solids is 2.7.
Find wet unit weight and dry unit weight:
How I'm trying to solve it: First i'm gonna find volume of solids and volume of water. I take the weight of solids to be .214 lbs and weight of water to be .018lbs. Using the formula I get .00127 for Vs and .000288 for Vw, which gives me something like 137 pcf for dry unit weight. Anyone help with where I made a mistake? My answer choices are 102, 112, 115, 122