Shallow Foundation with water level

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PE_2009

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If water level is between base of foundation & ground level, which formula should we use to calculate bearing capacity? Results are much different between CERM formula & NAVFAC formula. Is NCEES expecting us to use any particular formula in exam? Can somebody help me?

 
If water level is between base of foundation & ground level, which formula should we use to calculate bearing capacity? Results are much different between CERM formula & NAVFAC formula. Is NCEES expecting us to use any particular formula in exam? Can somebody help me?

Answer will be different, if we solve problem 56 from 6 minute solutions by using equation from NAVFAC, which is

Qultimate = 1.3cNc + [gamasubmerged x D + (gamatotal - gamasubmerged)d]Nq + [0.6 x gamasubmerged x R x Ngama]

in which D = depth of foundation below ground surface, d = depth of water level below ground surface & R = radius of circular footing

Can anybody help please?

 
If water level is between base of foundation & ground level, which formula should we use to calculate bearing capacity? Results are much different between CERM formula & NAVFAC formula. Is NCEES expecting us to use any particular formula in exam? Can somebody help me?

Answer will be different, if we solve problem 56 from 6 minute solutions by using equation from NAVFAC, which is

Qultimate = 1.3cNc + [gamasubmerged x D + (gamatotal - gamasubmerged)d]Nq + [0.6 x gamasubmerged x R x Ngama]

in which D = depth of foundation below ground surface, d = depth of water level below ground surface & R = radius of circular footing

Can anybody help please?
I think for the test use the CERM eqn qult = 1/2(gama')BNySy +cNcSc + (pq+(gamma-dryDf +gamma-water(Df-Dw))Nq

0r qult = .5[(1.16)(109.5) -62.4](2R)NySy + cNcSc + [(109.5)4 + 62.4(2.5-4)]Nq

This question kind of throws me.

I am confused why the last term uses gamma -dry, I would have thought it should be [(1.04gamma-dry(Dw) +(1.16gamma-dry - gamma-water(Df-Dw)]Nq.

I think you stumbled onto to something real confusing here. I sure do not know the answer. Somebody help please.

 
If water level is between base of foundation & ground level, which formula should we use to calculate bearing capacity? Results are much different between CERM formula & NAVFAC formula. Is NCEES expecting us to use any particular formula in exam? Can somebody help me?

Answer will be different, if we solve problem 56 from 6 minute solutions by using equation from NAVFAC, which is

Qultimate = 1.3cNc + [gamasubmerged x D + (gamatotal - gamasubmerged)d]Nq + [0.6 x gamasubmerged x R x Ngama]

in which D = depth of foundation below ground surface, d = depth of water level below ground surface & R = radius of circular footing

Can anybody help please?
I think for the test use the CERM eqn qult = 1/2(gama')BNySy +cNcSc + (pq+(gamma-dryDf +gamma-water(Df-Dw))Nq

0r qult = .5[(1.16)(109.5) -62.4](2R)NySy + cNcSc + [(109.5)4 + 62.4(2.5-4)]Nq

This question kind of throws me.

I am confused why the last term uses gamma -dry, I would have thought it should be [(1.04gamma-dry(Dw) +(1.16gamma-dry - gamma-water(Df-Dw)]Nq.

I think you stumbled onto to something real confusing here. I sure do not know the answer. Somebody help please.
That is really confusing part. What, if gamma dry is not given in exam? How can you use CERM?

 
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