Quiz #20

[ptatohed]

[SIZE=medium]An intersection has experienced 52 accidents in the last year. The average 24-hour volume of vehicles entering the intersection was measured to be 975, 1255, 1570, and 1465. What is most nearly the accident rate of the intersection, in accidents per million entering vehicles?[/SIZE]

[SIZE=medium]A.) 13[/SIZE]

[SIZE=medium]B.) 27[/SIZE]

[SIZE=medium]C.) 52[/SIZE]

[SIZE=medium]D.) 98[/SIZE]

 

[BLG923PE]

Good question ptato...my answer is B

 

[John QPE]

B - 27 per MVM

Work by request.

Big23 ..... Check your PMS

 

[BLG923PE]

Returned your PM John

 

[ptatohed]

B - 27 per MVM

Work by request.

Big23 ..... Check your PMS

Good job guys. Answer B is correct.

JQ, would you mind posting the solution please?

Thanks.

 

[nda]

ptatohed, thanks for the quiz. To clarify, is this intersection has four legs and ADT represent each leg?

Thank you

 

[ptatohed]

ptatohed, thanks for the quiz. To clarify, is this intersection has four legs and ADT represent each leg? Thank you

You're welcome.

Correct. I thought about listing in the problem statement that it is a 4 legged intersection but then I decided..... Nah, let me just provide them with 4 ADTs and they can take it from there.

 

[John QPE]

R = ( # accidents)(10^6) / (ADT)(# of Years)(365 days)

R = (52)(10^6) / (975+1255+1570+1465)(1)(365) = 27.06 accidents per MVM

* The problem says MVM so we use 10^6 in the numerator. If it asks for HMVM you use 10^8