Quiz #14

Professional Engineer & PE Exam Forum

Help Support Professional Engineer & PE Exam Forum:

This site may earn a commission from merchant affiliate links, including eBay, Amazon, and others.

John QPE

Straight Outta Compton
Joined
Oct 29, 2012
Messages
1,055
Reaction score
208
A sag vertical curve descends at -1.5% and meets an ascending grade of 3.0% at station 15+00 with elevation 111.45.

The length of the vertical curve is 1400 ft.

BVC Station = 8+00; Elevation = 121.95

EVC Station = 22+00; Elevation = 132.45

A 100-year storm event floods the roadway to elevation 125.00

The length of roadway (feet) that lies below the 100-year storm elevation is most nearly:

A) 1,219

B) 1,256

C) 1,312

D 1,416

 
So, for clarity, the 111.45 is the elevation at the PVI, not a point on the curve?
If one - tangent grade meets another + tangent grade, as stated, that's the PVI by definition. I like how the question is worded. It makes you stop and think for a second without making it obvious. :D

 
So, for clarity, the 111.45 is the elevation at the PVI, not a point on the curve?
If one - tangent grade meets another + tangent grade, as stated, that's the PVI by definition. I like how the question is worded. It makes you stop and think for a second without making it obvious. :D


I think the way it is worded is the 111.45 is on the curve. But I know PE problems always give PVI sta/el and not the el on the curve at the PVI, so I asked. I think the term PVI should be used in the problem statement if that's what the elevation is referring to.

 
So, for clarity, the 111.45 is the elevation at the PVI, not a point on the curve?
If one - tangent grade meets another + tangent grade, as stated, that's the PVI by definition. I like how the question is worded. It makes you stop and think for a second without making it obvious. :D




This was exactly what I was thinking .... but I wasn't really concerned with PVI here ....

I know there are a few guys taking transpo in April that have been following along, so I'll let this one sit for a few days, I'll email you my solution.

 
Last edited by a moderator:
So, for clarity, the 111.45 is the elevation at the PVI, not a point on the curve?
If one - tangent grade meets another + tangent grade, as stated, that's the PVI by definition. I like how the question is worded. It makes you stop and think for a second without making it obvious. :D


I think the way it is worded is the 111.45 is on the curve. But I know PE problems always give PVI sta/el and not the el on the curve at the PVI, so I asked. I think the term PVI should be used in the problem statement if that's what the elevation is referring to.
Considering how you like to sometimes write tricky questions, I figured you'd appreciate how it was worded. ;) As it stands, I feel that it's worded adequately and PVI was the obvious intention, IMO. But I do see where you're coming from.

 
So, for clarity, the 111.45 is the elevation at the PVI, not a point on the curve?
If one - tangent grade meets another + tangent grade, as stated, that's the PVI by definition. I like how the question is worded. It makes you stop and think for a second without making it obvious. :D




This was exactly what I was thinking .... but I wasn't really concerned with PVI here ....

I know there are a few guys taking transpo in April that have been following along, so I'll let this one sit for a few days, I'll email you my solution.


I know you weren't concerned with the PVI, that's why I asked. If it were a point on the curve, that'd change everything. ;) Thanks, got it. :)

So, for clarity, the 111.45 is the elevation at the PVI, not a point on the curve?
If one - tangent grade meets another + tangent grade, as stated, that's the PVI by definition. I like how the question is worded. It makes you stop and think for a second without making it obvious. :D


I think the way it is worded is the 111.45 is on the curve. But I know PE problems always give PVI sta/el and not the el on the curve at the PVI, so I asked. I think the term PVI should be used in the problem statement if that's what the elevation is referring to.
Considering how you like to sometimes write tricky questions, I figured you'd appreciate how it was worded. ;) As it stands, I feel that it's worded adequately and PVI was the obvious intention, IMO. But I do see where you're coming from.


LOL. We're getting off topic but.... If it said g1 and g2 meet at sta x and elev y, then I would agree. But it starts off with "A sag vertical curve descends.... " . A sag vc is a real entity. A PVI is an imaginary point. If it says "A sag vertical curve .... with elevation 111.45" I am going to assume it is on the actual physical curve, not an imaginary point, unless specifically told otherwise. :p

 
John,

Glad that you brought it up. I had to think about it for a little while.

I got the same answer as Ptatohed, it is C

Honestly, it took me more than 6 mins :suicide1:

 
But now that you know how to do it, and set it up, its not going to take more than that, right?? I was lost on this at first.

Put this one in your binder.

 
Last edited by a moderator:
Yes, difenatley this one is going to be in my afternoon binder.

 
So, for clarity, the 111.45 is the elevation at the PVI, not a point on the curve?
If one - tangent grade meets another + tangent grade, as stated, that's the PVI by definition. I like how the question is worded. It makes you stop and think for a second without making it obvious. :D




This was exactly what I was thinking .... but I wasn't really concerned with PVI here ....

I know there are a few guys taking transpo in April that have been following along, so I'll let this one sit for a few days, I'll email you my solution.


I know you weren't concerned with the PVI, that's why I asked. If it were a point on the curve, that'd change everything. ;) Thanks, got it. :)

So, for clarity, the 111.45 is the elevation at the PVI, not a point on the curve?
If one - tangent grade meets another + tangent grade, as stated, that's the PVI by definition. I like how the question is worded. It makes you stop and think for a second without making it obvious. :D


I think the way it is worded is the 111.45 is on the curve. But I know PE problems always give PVI sta/el and not the el on the curve at the PVI, so I asked. I think the term PVI should be used in the problem statement if that's what the elevation is referring to.
Considering how you like to sometimes write tricky questions, I figured you'd appreciate how it was worded. ;) As it stands, I feel that it's worded adequately and PVI was the obvious intention, IMO. But I do see where you're coming from.


LOL. We're getting off topic but.... If it said g1 and g2 meet at sta x and elev y, then I would agree. But it starts off with "A sag vertical curve descends.... " . A sag vc is a real entity. A PVI is an imaginary point. If it says "A sag vertical curve .... with elevation 111.45" I am going to assume it is on the actual physical curve, not an imaginary point, unless specifically told otherwise. :p
To me, the key word is the verb/action word "meets".. Besides, the part "at station 15+00 with elevation 111.45" immediately follows "meets an ascending grade"...What else could 'meet' there except the PVI. :p

 
Those who have answered have been contacted.

Does anyone else want to give this a shot? I can help you out if you need.

 
So, for clarity, the 111.45 is the elevation at the PVI, not a point on the curve?
If one - tangent grade meets another + tangent grade, as stated, that's the PVI by definition. I like how the question is worded. It makes you stop and think for a second without making it obvious. :D




This was exactly what I was thinking .... but I wasn't really concerned with PVI here ....

I know there are a few guys taking transpo in April that have been following along, so I'll let this one sit for a few days, I'll email you my solution.


I know you weren't concerned with the PVI, that's why I asked. If it were a point on the curve, that'd change everything. ;) Thanks, got it. :)

So, for clarity, the 111.45 is the elevation at the PVI, not a point on the curve?
If one - tangent grade meets another + tangent grade, as stated, that's the PVI by definition. I like how the question is worded. It makes you stop and think for a second without making it obvious. :D


I think the way it is worded is the 111.45 is on the curve. But I know PE problems always give PVI sta/el and not the el on the curve at the PVI, so I asked. I think the term PVI should be used in the problem statement if that's what the elevation is referring to.
Considering how you like to sometimes write tricky questions, I figured you'd appreciate how it was worded. ;) As it stands, I feel that it's worded adequately and PVI was the obvious intention, IMO. But I do see where you're coming from.


LOL. We're getting off topic but.... If it said g1 and g2 meet at sta x and elev y, then I would agree. But it starts off with "A sag vertical curve descends.... " . A sag vc is a real entity. A PVI is an imaginary point. If it says "A sag vertical curve .... with elevation 111.45" I am going to assume it is on the actual physical curve, not an imaginary point, unless specifically told otherwise. :p
To me, the key word is the verb/action word "meets".. Besides, the part "at station 15+00 with elevation 111.45" immediately follows "meets an ascending grade"...What else could 'meet' there except the PVI. :p


LOL. It is clear that the station 'meets' there.... but not the elevation. LOL. :p

 
Finally I'm able to use the forum!. Exited!.. I tried this problem and I can't get passed the point where I find the station at which the flow line touches the curve (X=11.05 stat, from BBC. Or 19+05. Now what do I do?

 
Well if you have the 11+09 stations you are 99% of the way there.

Draw this out ....

Now on your back tangent, figure out what station elevation 125.00 hits [(125 - 111.45) / 0.015] = 903.33 .... so you know elevation 125.00 hits 903.33 feet up the tangent. 1500-903.33 = 596.67 (STA 5+96.67)

the difference in station between the back and forward tangents is the amount underwater.

You have 203.33 feet along the tangent, and 1109 feet along the curve so: 1312.33 feet underwater

My solution below

https://www.mediafire.com/?spvrjoymfmmtq3w

 
Back
Top