Practice Problem Camara 27-6

[clemente]

Question:

A voltage of 10cos(100t +25 degrees) is applied to a resistance of 25ohm and an inductance of .5H in parallel. a) What are the phase Angle and B) rms values of the sum of the currents?

My answer was off from the book,

their solution is as follows.

Ir = (10<25)/25

in rectangular = .3625 + j.1690

IL = (10<25)/ ((.5)(100)<90)

Its probably something simple but where did they get the 100?

 

[cabby]

Question: A voltage of 10cos(100t +25 degrees) is applied to a resistance of 25ohm and an inductance of .5H in parallel. a) What are the phase Angle and B) rms values of the sum of the currents?

My answer was off from the book,

their solution is as follows.

Ir = (10<25)/25

in rectangular = .3625 + j.1690

IL = (10<25)/ ((.5)(100)<90)

Its probably something simple but where did they get the 100?

The 100 is omega from the 100t. X(L)=omega * inductance

See the attached

Hope this helps.

 

[clemente]

The 100 is omega from the 100t. X(L)=omega * inductance
See the attached

Hope this helps.

Helped greatly, thanks.

X(L)= j omega L. i can't beleive i forgot about the omega.