power EE test question

[sd3232]

please look at attached file for question and answer, i dont get the answer, can someone explain this one to me? answer says phase to ground is equal to phase to phase, VBG=VBA=13.2kV, i thought phase to ground was 7.62kV? why is C a right answer? thanks

 

[VolInGA]

please look at attached file for question and answer, i dont get the answer, can someone explain this one to me? answer says phase to ground is equal to phase to phase, VBG=VBA=13.2kV, i thought phase to ground was 7.62kV? why is C a right answer? thanks

Draw it out. You should see that the phase-phase voltage will be the same as the phase-ground voltage for that leg.

 

[Flyer_PE]

If you ground one leg of a delta system (or ungrounded wye for that matter), the magnitude of the voltage between either of the other two legs and ground will be the line voltage (VL-L).

 

[Jonjo]

please look at attached file for question and answer, i dont get the answer, can someone explain this one to me? answer says phase to ground is equal to phase to phase, VBG=VBA=13.2kV, i thought phase to ground was 7.62kV? why is C a right answer? thanks

sd3232 , The system is "ungrounded" the grounding point is floating for this system there is not going to draw any current also

 

[sd3232]

thanks guys, but its still fuzzy to me, is it 13.2kV because on delta phase to ground voltage is equal phase to phase? if some one could provide a sketch, i will keep reading the response and may be i will get it, need some time

 

[bambooi]

thanks guys, but its still fuzzy to me, is it 13.2kV because on delta phase to ground voltage is equal phase to phase? if some one could provide a sketch, i will keep reading the response and may be i will get it, need some time

The explaination is in the answer. There is no ground path.just like some one said above the system is floating.