Hi everyone. I'm new to the board and didn't see a topic on this question. The question refers to a 3-phase transmission line where you have to solve for the capacitive reactance of the line, and then find the charging current. I'm confused on one thing:
In the solution, they show the math for solving for capacitance using the line to ground capacitance equation given in the question. The equation is C = 0.0388 / log(Deq/Rc). With Deq = 12.57 and Rc = .429, the solution shows the following:
C = .0388 / log(12.57)/(.0429 X 12) = .0152 uF/mile
Can someone help with this calculation? I'm not sure where the 12 came from, and not sure why the log calculation is different from the given equation. This seems like such an easy problem, but my brain has apparently quit on me this morning.
Thanks for any assistance!
In the solution, they show the math for solving for capacitance using the line to ground capacitance equation given in the question. The equation is C = 0.0388 / log(Deq/Rc). With Deq = 12.57 and Rc = .429, the solution shows the following:
C = .0388 / log(12.57)/(.0429 X 12) = .0152 uF/mile
Can someone help with this calculation? I'm not sure where the 12 came from, and not sure why the log calculation is different from the given equation. This seems like such an easy problem, but my brain has apparently quit on me this morning.
Thanks for any assistance!