maximus808
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- Mar 14, 2009
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Can someone please clarify the following problem:
1. Given the following data:
Time (hrs) vs. Discharge (cfs)
0,0
1,75
2,200
3,100
4,50
5,25
6,0
A two hour storm even of intensity 0.5 in.hr.
How much EXCESS VOLUME of water (acre-ft) is produced?
The answer sets up a table of Time, Qu, Q1 + Q2 = Qtotal. It adds the Qtotal then x 3600s/hr x 1ac/43560 ft^2 = 37.19 ac. ft.
What does Qu, Q1, and Q2 represent and how are these factors determined? thanks.
1. Given the following data:
Time (hrs) vs. Discharge (cfs)
0,0
1,75
2,200
3,100
4,50
5,25
6,0
A two hour storm even of intensity 0.5 in.hr.
How much EXCESS VOLUME of water (acre-ft) is produced?
The answer sets up a table of Time, Qu, Q1 + Q2 = Qtotal. It adds the Qtotal then x 3600s/hr x 1ac/43560 ft^2 = 37.19 ac. ft.
What does Qu, Q1, and Q2 represent and how are these factors determined? thanks.