Ramnares P.E.
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- Feb 6, 2013
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519. Shouldn't the calculation of the mass flow rate use the given efficiency? The equation would then look like:
P = [m(h1-h2) + 0.9m(h2-h3)] / eff which would result in 87000 lbm/hr instead of 75689.88 lbm/hr.
525. In the calculation of the fuel masses, where do the coefficients 2, 3, and 4 come from?
m(H2O) = 18[2(0.859) + 3(0.052) + 4(0.015)]
Thanks.
P = [m(h1-h2) + 0.9m(h2-h3)] / eff which would result in 87000 lbm/hr instead of 75689.88 lbm/hr.
525. In the calculation of the fuel masses, where do the coefficients 2, 3, and 4 come from?
m(H2O) = 18[2(0.859) + 3(0.052) + 4(0.015)]
Thanks.
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