NCEES # 129 : Voltage drop

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RBsai

Project Engineer
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May 28, 2013
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Can anyone explain me why ncees soln considered the drop at the panel as phase instead of line ??

I am getting 475V as an answer.

Z= 0.00725+0.0120j

Voltage drop at the panel = 480 - IZ(drop)

 
Since the impedance is per phase take 480/sqr3 minus the phase drop then convert back to line.

 
Can you guys tell me if CI Volume 2 (ver 2) problem #12 is incorrect and should be solved the same way as NCEES #129 with Phase Voltage instead of Line voltage?

3 phase system serves balanced load of 230 A at lag PF= -.75, 500 ft of 350 AWG uncoated CU in PVC.

 
Nevermind, lol. It states in the question that the given voltage is the Phase Voltage. :beat:

 
It seems 90% of my wrong answers on practice tests stem from not fully reading the question!

 
You are not alone. Just carefull tomorrow. .. i will read questions twice.

Good luck for all of us....

 
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