Complex Imaginary Volume 2 Problem 24

[Insaf]

Answer should be 589 Volt, any thoughts?

Thanks!!

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Voltage Drop (L-N) = I[RCos(theta) + X sin(theta)]

= 230 (.019x0.75 + .02x 0.661) [ sin (Theta)=0.661]

= 6.31 volts

Voltage Drop (L-L) = 1.732x6.31=10.93 volts

So Terminal voltage = 600-10.93=589.07 volts

(for formula ref - ieee 141)

 

[one4snow]

I agree with your set up but I Believe that R=.038 for uncoated copper wires in a PVC conduit. What does everyone else think?

 

[DK PE]

You're going to have to provide a few more details for those of us that don't have CI exams? Conductors ? distance? etc