Thanks for the info. Everybody I talked to that passed the last couple of times had their names/license numbers on Lapels within a couple of days of knowing they passed. I was expecting a similar timeframe here, oh well.
I've looked at the dates for the past couple of tests, and it looks like the "Date Issued" for the licenses have started within a day of the test results being available. I don't know if that means the license numbers were posted on the state board website on that date or if that's the date...
I don't have a good answer. The only thing I can think of is that they're specifiying kVar vaules instead of farad values of the capacitors, so if you have 140kVar units connected in parallel, you get that kVar value at full voltage. If you connect 140kVar units in series, you get that kVar...
I don't have this volume. Can you give a little more info about their solution? Is it 8 per phase? Do they give you the operating voltage and rated voltage?
This is what I did using 240 for the Phase C voltage:
Ia=(120+65i)/(19.9 @ 0) = 6.86@28 => 6.86@-28
Ic=(65+20i)/(19.9@240) = 3.42@137 => 3.42@-137
In= 3.42@-137 + 6.86@-28 = 6.59@-57A
This is question 69 in the newer edition. I had the same question and e-mailed Complex Imaginary. Their explanation was that since they didn't specify any of the conditions in 240.4(B'), you can't use that rule.
FYI, I emailed CI and they replied with:
Because 240.4(B)(1-2) are not specified in the question. Therefore - them NOT being included in the problem - we cannot assume that it meets these conditions. Especially for code questions, you cannot assume that conditions are met that are not...
The code (240.4(B)) says that up to 800A you can go above the cable rating if there is no standard trip rating that corresponds to the cable rating. In this case, 190A isn't a standard trip rating, but 200A is.
I answered 200A since that would be the next standard rating above the 190A rating for the conductor in the NEC. The solution says it should be less than or equal to the conductor rating and the answer is 180A. Is there something in the problem that does't allow you to use the "next standard...