Recent content by FelizEng PE

Hey - sorry for the late reply - haven't been on for a while.  If I am understanding correctly, Stardust is currently a PE in California and wants to become a licensed PE in the state of NY.  Don't think I could be of help - I never applied for reciprocity.  

I've been rooting for you and waiting on your successful result!! Go MadamPirate! 

Hello my friend. I hope all is well - I like that you are being proactive in seeking information to best prepare for the exam. This kind of energy is needed to attain favorable results. I started studying with the code book for about a month and then decided to purchase the handbook. In my...

@LyceeFruit I am sooooo happy that you got yours.  I also wanted to take the time to thank you for helping me through my prep - I honestly could not had done it without you kindly providing me the direction to prepare.  I wish you nothing but the best and more.  I am really really happy right...

2019: Passed FE & PE Received notice at 1:55 PM EST Time

Passed FE & PE in this year 2019 Received notice at 1:55 PM EST Time

Hey Takk90, The question asks "According to the NEC" and therefore you must use the motors' NEC FLC used to size of conductors.  The author dropped the 125% on the latest errata:  https://www.engproguides.com/powerreferenceexamerrata.pdf (Since 125% is for wire sizing, but we are just trying...

Hello - hope all is well. For Minimum Motor Conductor Ampacity, lookup the motors FLC using HP and voltage rating from NEC Tables 430.247-250. Do not use the motors nameplate FLC. If conductor serves only one motor that is continuous duty, multiply FLC (found on tables) by 125%. Hope this helps.

Thank you very much for your input

Does the EngPro Final exam differ much from the Full Exam?

For me would be the ones I’m familiar with LOL, being that I took the course in graduate school and so it comes back to me relatively quick compared the topics I’ve never seen: 3ph Power, fault analysis, rotating matches (somewhat - my power systems course touched upon this subject lightly)...

I appreciate everyone who has taken their time to provide input. All is very value information [emoji1545].

For me, I have found best in creating my own formula sheet as I am going through problems/topics (kind of like a condensed version of the study guides because I am writing notes as well). I am using graffaeo/eng proguides/the essential text book resources mentioned here.

Could see the prob? I have never seen current conj used to obtain the real power

Yes you are correct.  What I do is convert all Voltages & Currents to their phase values and apply:  V1/V2 = I2/I1  And hence solving for Vtransmission line: Vline (on Wye-side of TX1) = sqrt(3) * 12.47kV *[1130.36A/(122.57A*sqrt(3))] The root 3's cancel out and you are left with Vline...