C cabby Well-known member Joined Aug 8, 2007 Messages 48 Reaction score 0 Sep 25, 2007 #1 In the Kaplan Electrical Exam solutions, problem 1.1, I can not figure out how they went from e^-j5 and ended up with an angle of 73.5211 degrees. Has anyone worked this yet? thanks,
In the Kaplan Electrical Exam solutions, problem 1.1, I can not figure out how they went from e^-j5 and ended up with an angle of 73.5211 degrees. Has anyone worked this yet? thanks,
Dark Knight Silent Guardian Joined Jun 8, 2006 Messages 3,617 Reaction score 310 Location Central Florida Sep 25, 2007 #2 The angle 73.52 comes from doing the multiplication of e-.5 and e-j5. You know,equal bases, so add the exponents. It come like this: e(-.5 - j5). That will give you the .6065<73.52. Hope I answered your question.
The angle 73.52 comes from doing the multiplication of e-.5 and e-j5. You know,equal bases, so add the exponents. It come like this: e(-.5 - j5). That will give you the .6065<73.52. Hope I answered your question.