Kaplan Exam prob 1.1

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cabby

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In the Kaplan Electrical Exam solutions, problem 1.1, I can not figure out how they went from e^-j5 and ended up with an angle of 73.5211 degrees. Has anyone worked this yet?

thanks,

 
The angle 73.52 comes from doing the multiplication of e-.5 and e-j5. You know,equal bases, so add the exponents.

It come like this: e(-.5 - j5).

That will give you the .6065<73.52.

Hope I answered your question.

 
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