This problem involves computing the power output of a 3-phase induction generator which is connected to a wye system. You are given the full load output of 325A and the generator nameplate rating of 2.4 kV.
My thought was that the apparent power should be calculated as such:
(1) S=Vp*I*sqrt(3)
But the solution uses:
(2) S=3*Vp*I
In both equations Vp= phase voltage and I= line current = phase current.
I based my formula on the fact that we calculate the size of a transformer similarly. If I need a 480VD to 208Y/120V transformer size, I will take the amps I have on the 208Y/120V panel and multiply that by 208*sqrt(3) or:
(3) KVA=Vp*I*sqrt(3) which is the same as (1)
Can anyone explain why I would use (2) instead of (1)???
My thought was that the apparent power should be calculated as such:
(1) S=Vp*I*sqrt(3)
But the solution uses:
(2) S=3*Vp*I
In both equations Vp= phase voltage and I= line current = phase current.
I based my formula on the fact that we calculate the size of a transformer similarly. If I need a 480VD to 208Y/120V transformer size, I will take the amps I have on the 208Y/120V panel and multiply that by 208*sqrt(3) or:
(3) KVA=Vp*I*sqrt(3) which is the same as (1)
Can anyone explain why I would use (2) instead of (1)???