Man I hate that if I don't work problems for a while I have a hard time with the most trivial things. Use it or lose it. I have been working for a utility for a while and I came from the consulting world. We calculate voltage drop for services and here are my questions:
We try to keep our voltage drop to 5% which is the NEC recommendation. We include the voltage drop across the transformer along with the drop in the conductors. I have no problem with the voltage drop across the conductors using NEC's way. I am not sure if anyone else includes the drop across the xfmr and how accurate does it need to be.
We don't get X and R values just %Z. Say I have a 50kVA, 3phase, 4%Z, 208/120V xfmr. The load is 3 phase, with 20kVA demand.
One way I have seen is (.04)(20/50)(208)=3.3. Another way would be using FLA and Z. 20kVA = 55.5A. (55.5)(.04)=2.22
What is correct or incorrect about these calcs. I am definitely missing something and this should be super easy.
Another thing we calculate is Flicker. It seems to me that it is voltage drop due to inrush of a motor starting. It seems like it should be similar to one of the above calcs except the load is the FLA of the motor multiplied by 5 or 6 to get inrush amps.
Thanks in advance.
We try to keep our voltage drop to 5% which is the NEC recommendation. We include the voltage drop across the transformer along with the drop in the conductors. I have no problem with the voltage drop across the conductors using NEC's way. I am not sure if anyone else includes the drop across the xfmr and how accurate does it need to be.
We don't get X and R values just %Z. Say I have a 50kVA, 3phase, 4%Z, 208/120V xfmr. The load is 3 phase, with 20kVA demand.
One way I have seen is (.04)(20/50)(208)=3.3. Another way would be using FLA and Z. 20kVA = 55.5A. (55.5)(.04)=2.22
What is correct or incorrect about these calcs. I am definitely missing something and this should be super easy.
Another thing we calculate is Flicker. It seems to me that it is voltage drop due to inrush of a motor starting. It seems like it should be similar to one of the above calcs except the load is the FLA of the motor multiplied by 5 or 6 to get inrush amps.
Thanks in advance.