Is it safe to assume that whenever a pressure problem is given in psia or psig, the formula for pressure= (P=rho*h), remains the same. So if i want to convert psig to psia, what is the method to do so? I know that p(atm)=p(abs) + p(vacuum). But what is absoulte P in simple terminology? I get a little worried whenever I see the question shifting from psia to psig, even though I understand the concept of psai and psig, but not p(abs).
A little guidance here on this matter is very much appreciated. Just don't want to give away easy points on the exam over carelessness....
Thank you..
A little guidance here on this matter is very much appreciated. Just don't want to give away easy points on the exam over carelessness....
Thank you..