Stephen2awesome
Well-known member
Problem asks the required capacitance to correct the power factor. 60Hz, 3-ph, 208V load of 200+150j. I got C = 9.2uF but the answer is 1/3 that. The answer uses the 208^2 divided by 50 (QVars/3) to find Xc then ultimately C. My question is why did the solution use the 3-phase voltage with the single phase portion of the load?