Peak Voltage from 3-phase generator to one dc motor

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BamaBino

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This is from Complex Imaginary Test#1 problem 70.

It has a 3-phase generator with each phase of 125V half-wave rectified and connected to the input of one dc motor.

It asks what is the peak voltage across the dc motor input?

They answer given is 125*1.73=217V.

I don't think this answer is correct. Should the square of 2 be part of the solution since it is asking for PEAK voltage?

Thanks

 
Isn't supposed to be.

phase voltage is 125V

Line to line voltage =125V x square of 3=216.5V

Peak voltage line to line = 216.5V x square of 2=306.18V

 
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