I don't follow the NCEES solution to this problem, can anyone shed some light as to what values mean what? I can't seem to piece it together.
Q:
Consider the voltage waveform, x(t), which is the output of an amplitude-modulated (AM) transmitter:
x(t) = 40 cos (200,000pi t) + 10 cos (197,000pi t) + 10 cos (203,000pi t)
The percentage of modulation of the AM waveform, x(t), is most nearly:
( A ) 25
( B ) 33
( C ) 50
( D ) 75
A:
x(t) = 40 cos (200k pi t) + 10 cos (197k pi t) + 10 cos (203k pi t)
x(t) = 40 [cos (200k pi t) + 0.25 cos (197k pi t) + 0.25 cos (203k pi t)]
(Here's where I get lost - didn't see this in the EERM
max [1/2 m(t)] / A sub c = 0.25
max [ m(t)] = 20
Mod = 2 max [1/2 m(t)] / A sub c = 0.5 -> 0.5 * 100 = 50%
Any help would be appreciated. Trying to get some "last-minute" concepts down before Friday.
Q:
Consider the voltage waveform, x(t), which is the output of an amplitude-modulated (AM) transmitter:
x(t) = 40 cos (200,000pi t) + 10 cos (197,000pi t) + 10 cos (203,000pi t)
The percentage of modulation of the AM waveform, x(t), is most nearly:
( A ) 25
( B ) 33
( C ) 50
( D ) 75
A:
x(t) = 40 cos (200k pi t) + 10 cos (197k pi t) + 10 cos (203k pi t)
x(t) = 40 [cos (200k pi t) + 0.25 cos (197k pi t) + 0.25 cos (203k pi t)]
(Here's where I get lost - didn't see this in the EERM
max [1/2 m(t)] / A sub c = 0.25
max [ m(t)] = 20
Mod = 2 max [1/2 m(t)] / A sub c = 0.5 -> 0.5 * 100 = 50%
Any help would be appreciated. Trying to get some "last-minute" concepts down before Friday.