NCEES 01 Q503

Professional Engineer & PE Exam Forum

Help Support Professional Engineer & PE Exam Forum:

This site may earn a commission from merchant affiliate links, including eBay, Amazon, and others.

Audi Driver P.E.

Well-known member
Joined
Sep 21, 2015
Messages
4,851
Reaction score
1,675
compressor_problem.pdf

Ok, so I am getting to where calculating required horsepower is not as difficult a task as it was when I started my exam prep. In reviewing the solution to the subject problem I am struck by the methodology used to calculate and convert temperatures. The basic issue is the order they do the operations. When I worked the problem, I chose to calculate T2 and T4 in Degrees F and then convert to Rankine. They convert first and then calculate.

The difference in methodology seems to be:

a) (x*y) + Z

vs.

b) (x+z) * y

Where X is the initial temp (i.e. T1 and T3), Y is the Temperature calculation "factor" (for this problem it is equivalent to 1.51 for T1 to T2, and 1.45 for T3 to T4), and Z is the conversion to Rankine.

Using method "a" yields a T2 of 89 degrees F and 459 R.

Method "b" yields a T2 of 783 R which is 323 F.

I would think that, if the problem were to simply solve for T2 and T4 in degrees F, that the solution would yield T2=89F and T4=145F because conversion to Rankine would never even enter into the equation. Correct?

I chose to solve the problem using methodology "a" because I remembered that Delta T in F is equal to Detal T in R.

Am I nuts? or am I to assume I missed some requirement that the temperature calculation is only valid in absolute temperatures? Obviously, if the given solution is the only correct one, that is what i am assuming at this point.

 

Attachments

  • compressor_problem.pdf
    482.7 KB
Ok, I did some more research as to why my method "a" was wrong, and it is as I supposed, that the calculation factor (my terminology) does require the use of absolute temperature due to the equation being derived from the ideal gas law. Not sure how I missed that relationship, but I answered my own question at least.

Many thanks to those of you willing to bear with me. I suppose that sometimes I just need to reason things out like this.

 
Back
Top