John QPE
Straight Outta Compton
- Joined
- Oct 29, 2012
- Messages
- 1,055
- Reaction score
- 208
R = 1000'
Delta Angle = 16*38'
I'll leave out the rest of the problem as it's not relevant (I don't think it is)
So ... this problem was a basic HC problem, with several questions .. Find T, BC, EC, LC, L, E, M
So I solve for E and get 10.62 ft which was correct.
The next question is solve for M ...
So since E is still in my calculator I use M= E cos(Delta/2) which equals 10.18 ... not an answer choice.
I then use M = R(1-cos (Delta/2)) which equals 10.52 .... which is an option (and the correct one I might add)
So what gives? Is there a rule of thumb for these equations that I don't know about??
I'll make up a full HC problem tomorrow for the board.
Thanks
Delta Angle = 16*38'
I'll leave out the rest of the problem as it's not relevant (I don't think it is)
So ... this problem was a basic HC problem, with several questions .. Find T, BC, EC, LC, L, E, M
So I solve for E and get 10.62 ft which was correct.
The next question is solve for M ...
So since E is still in my calculator I use M= E cos(Delta/2) which equals 10.18 ... not an answer choice.
I then use M = R(1-cos (Delta/2)) which equals 10.52 .... which is an option (and the correct one I might add)
So what gives? Is there a rule of thumb for these equations that I don't know about??
I'll make up a full HC problem tomorrow for the board.
Thanks