Hiner Problem 11 Flexible Roof Diaphragm

[passpepasspe]

I was wondering if someone could help me with the Hiner Problem # 11 in Part 2 of the book.

the given information is that

-single story building

flexible roof diaphragm

average roof height = 11 ft

sesimic design catery E

seismic base shear V =100kips

Total force to wall lins 1 & 2 F1=F2=50 kips.

Determine the redunducancy factor p is permitted to be taken as 1.0 for N to South load direction assuming the vertical elementts of seismic force ressiting system SFRS on wall lines 1 and 2 are:

a. speicial reinforced concrete shear walls

b. special steel concentric braced frames

c. special steel moment frames.

I understand how to do part 1 by calculating the number of bays.

I don't understand how to look at the provided figure and determine the bays for part b and c.

maybe someone can help me understand the figure...

any help is appreciated...

 

[sac_engineer]

The problem is just knowing how many bays there are for each type of SFRS along the N-S walls. p=1 if the SFRS consists of 2 bays of SFR perimeter framing, otherwise p=1.3

A. Based on the L/h check, p=1 because the length of the wall is less than twice the height.

B. There's only 1 bay for the steel CBF (2 colums), thus p=1.3 since it doesn't meet the criteria for p=1.

C. There are 2 bays in the steel SMF (3 columns), thus p=1 since it meets the criteria

 

[passpepasspe]

The problem is just knowing how many bays there are for each type of SFRS along the N-S walls. p=1 if the SFRS consists of 2 bays of SFR perimeter framing, otherwise p=1.3
A. Based on the L/h check, p=1 because the length of the wall is less than twice the height.

B. There's only 1 bay for the steel CBF (2 colums), thus p=1.3 since it doesn't meet the criteria for p=1.

C. There are 2 bays in the steel SMF (3 columns), thus p=1 since it meets the criteria

i guess my problem is reading hte figures that are provided. I don't have any experience in siemsic or structures, so I guess it might be a stupid question. hahah.

But for B and C , how do you finding out that there are 1 bay for B and 2 for C.