Help calculating Neutral current

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Sparky Bill PE

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When I solve this problem, I am using Load C and A to get my angle of current. I am giving the PF of the load, so I am taking the conjugant. In this solution It is using 240-angel and 120-angle and I don't know why they are doing that when finding current. 

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Apart from the angles, shouldn't Ib in the addition for In be negative? If we do KCL, Ia and Ic will be leaving the neutral point N and Ib will be entering it. Or am I missing something?

 
Yeah, I remember this was a weird solution off of the Spin up Exams. This solution really doesn't make sense to me either, it seems incorrect.

 
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