I'm trying to understand the concept of phase sequence and came across two similar examples in Grainger's Power System Analysis but solved differently. One example add in the 30 deg angle when go from line voltage to phase voltage and a another example not.
example 1.2
In a balanced three-phase circuit, the voltage Vab is 173.2<0deg. Determine all the voltages and currents in the Y-connected load having Z=10<20 ohm. Assume that the phase sequence is abc.
solution: Vab = 173.2<0 Van = 100<-30
Vbc = 173.2<240 Van = 100<210
Vab = 173.2<120 Van = 100<90
example 1.3
The terminal voltage of a Y-connected load consisting of three equal impedances of 20<30 ohm is 4.4kV line to line. The impedance of each of the three lines connecting the load to a bus at a substation is Z=1.4<75. Find the line-to-line voltage at the substation bus.
solution: Van = 2540<0 and Ian = (2540<0)/(20<30) = 127<-30
Why example 1.3 doesn't use the 30 deg angle when go from line voltage to phase voltage, but example 1.2 does?
example 1.2
In a balanced three-phase circuit, the voltage Vab is 173.2<0deg. Determine all the voltages and currents in the Y-connected load having Z=10<20 ohm. Assume that the phase sequence is abc.
solution: Vab = 173.2<0 Van = 100<-30
Vbc = 173.2<240 Van = 100<210
Vab = 173.2<120 Van = 100<90
example 1.3
The terminal voltage of a Y-connected load consisting of three equal impedances of 20<30 ohm is 4.4kV line to line. The impedance of each of the three lines connecting the load to a bus at a substation is Z=1.4<75. Find the line-to-line voltage at the substation bus.
solution: Van = 2540<0 and Ian = (2540<0)/(20<30) = 127<-30
Why example 1.3 doesn't use the 30 deg angle when go from line voltage to phase voltage, but example 1.2 does?