Digging this topic back up, because I still can't make sense of these!
For 129, the method posted above with Ze=R*pf + X*[sin(arccos(0.8))] I can understand, but then isn't the Ze=0.0232+j 0.0288? Not seeing how to get 0.052 Ohm-N...
Also the NEC and previous poster note that the R and X...