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Correct, your calculation based on the rated values of the generator gives the rated current. The 'load current in the generator' that the question is looking for is the 75.93A reflected across the transformer. The impedance of the transmission line does not come in to play on this problem...

Good call Gabe. That is the mistake I made; I was factoring in the delta-wye configuration when I was calculating the line current, but not when calculating the turns ratio first. Without skipping that step I would factor in the sqrt(3) in to the turns ratio calculation, and then it ends up...

GabeM, this is what I thought, however the correct answer was 760A. Flyer, I wasn't given the turns ratio, but calculated it from the voltages easily enough (a=Vp/Vs). I'm still not clear though on why the delta-wye configuration doesn't come into play. Can you elaborate on this a bit more...

This problem describes a secondary transmission line with a current of 75.93A and voltage of 132kV fed from a generator on the primary (at 13.2 kV) thru delta-wye transformer. The question is: "The load current in the generator is most nearly..." When I solved the problem, I assumed it was...