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So how did you get R=3 and X=4? Adding up the equivalent resistance/reactance and coverting to actual values given the base of 20kVA?

The solution is rather simple but it doesn't make sense..... Zp= sqrt(R^2+Xl^2 angle (arc tan X/R)) Quantities for R and X are 3 and 4 respectively. First off any idea how they came up with the numerical vaules for R and X?

Anyone work through this question: Camara sample test, power morning #40? See attached PE_exam.pdf