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Ok, so the answer for this problem requires dividing the transformer power by 3, not root 3. It's 3 phase, wye connected. Why do we divide power by 3 to find output per phase in order to find current?

Ok, So I am lost on this problem. Why do we sum the 3H, and what are we summing, 3A per phase? Anyone have a good read on harmonic calcs?

Ok, so am I getting this right: Per Phase VAR = I^2 * X (X is reactance) 3 Phase Var = 3*I^2 * X To me this does not seem intuitive as with KW we always utilize root 3. Anyone have a good article on this or brief explanation?