Search results

Here is how I approached this problem. We are told that the s.c. test was done at rated current. I assumed a value of 1pu for the current, and we were given Zpu = 0.1. From there it was just V=IZ, and then turning the pu voltage into actual voltage.

In problem 517, the synchronous motor is said to have a leading pf of .7, and the solution shows the pf angle to be negative. Then for the the induction motor, which is said to have a lagging pf, they show the angle of this machine to be positive. This actually agrees with the EE Reference...

I bought the 8th edition and then received the 7th from someone who passed last october. after glancing through the 7th ed., it really looks almost exactly the same, although i admit i did not do a really thorough examination. The book itself is helpful, but not great. I found the chapters on...

I seem to have a mental block or something when it comes to rotating machines. I know this is kind of a broad topic, but does anyone have any advice or maybe a good reference? I have an old edition of theodore wildi's book, electical machines, drives, and power systems, that i have been...

got it now. thanks very much for the help.

FYI, If anyone out there is wondering, it is possible to receive credit for your co-op experience. I am going to be sitting for the exam in April, but without my co-op would not have been eligible until October. I contacted the state board ahead of time and sent them a summary of just my...

Flyer, thanks for the help. I get the concept now--you have to convert from the 40MVA base to the 1MVA base, correct? The equation you solved looks like the equation for converting from one base to another, but where did you get the value of 1.0 for the 40MVA per-unit impedance? Or am I...

#519: I'm feeling kind of lost on this one.....can someone explain? #530: OK, I think I get most of the given solution to this problem. It looks like they find the p.u. short-ckt current by dividing Vpu by total Zpu. Then they solve for the base short-ckt current by dividing S by sqrt of 3...