Search results

Per NEC Handbook Nse + Nc = 1440, Nc = 1200, SW = 60 kVA. Since it's a step up autotransformer: Sio = 60 kVA * 1200 / 1440 = 50 kVA. However, the answer is Where is my mistake?

Source: Practical Grounding, Bonding, Shielding and Surge Protection G. Vijayaraghavan Newnes An imprint of Elsevier 2004 ISBN 0 7506 6399 5

I was confused, this would give phase current, the primary is Delta. See below figure highlighted The Primary current = I The secondary current = a*I/1.732 = 62.7 A Solve for I = 62.7 * 1.732/0.762 =142.5 A

Hi, Can we have a forum for The Association of Energy Engineers (AEE)? They have many good certificates, the one I am interested in is AEE's Certified Green Building Engineer. https://www.aeecenter.org/certifications/certifications/green-building-engineer What do you think guys?

Can someone explain?

I think the answer should be 1/1.5, because the load impedance |Z| is 227 ohm and it will be reflected to the transformer primary?

Isn't I1 the phase current and the line current should be : 1.732 * 143 = 247 A?