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Thank you for sharing the solution! Im used to applying the pu method so to avoid trying to learn a method i will stick to that. However when determining the pu impedance for the given MVAsc i realized a mistake on my end. For example what i did was MVAsc= srt(3)*Vnom*Isc (Based on the NCEES...

Hello, In the sample question from the NCEES PE exam in the solution they consider a 30 Degree Phase shift between Phase to Phase and Phase to ground voltages From what i recall VAB leads Van by 30 deg which is why they place a -30 deg angle on Van However this is the first time i see one of...

For this question the sample Exam does not provide any diagrams, we only have the problem description.

Thank you so much! In your example where the source kV and XFMR primary kV dont match what would decide the base kv in that case? For the VT example i completely follow what you are saying. However if there was a load on the XFMR secondary for example then would my XFMR impedance...

Thank you for the detailed explanation. Let me just ask the following to make sure i understand this correctly: 1. When we select the BasekV this should represent the faulted bus voltage right? 2. Lets assume the question asks instead for the 3P fault current at "VT" Would this be the correct...

But isn't the Genarators impedance based on the Gens MVA and voltage base which in this case is 22kV ?

Hello, I was looking at the sample PE exam question below. When solving the question i decided to use the XFMR Secondary voltage and MVA as my base values. Which then required the Gen imp to be converted to the XFMR MVA base. When doing so the first time i followed the process below...

In the question below we are given the max demand for 4 different 15 min time periods. We are also told that the max demand at t=0 is 35kW With the given information for the average consumption at time interval 1 from that i understand refers to from t=0 to t=15 min which from the graph is 25...

Hello, In the question below we are after the 3Phase fault current on the secondary of a 12.47/0.480 kV XFMR. Now in addition to the XFMR parameters we are told the "Fault Duty" on of the 12.47kV side of the system. My interpretation is that this represents the equivalent MVAsc of the system...

Thanks akyip!

hello, In the sample question below the drop across the 1-Phase Cable is considered twice. I cant recall why this has to be done can someone please refresh my memory?

Thanks for the feedback Your method makes sense but the equations given by NCEES for luminous flux puzzle me now since the units dont work out Based on their variable definitions they Say "I" is the illuminance in candelas but for the luminous flux to work out does "I" not need to be in foot...

Thanks for the feedback. The only thing I'm wondering is there any way for me to use the equation below provided? My main concern is during the exam what i will have are NCEEs equations. So i prefer to be able to use them in the event i blank out and forget the shortcut you have provided.

I tried looking at the question below and I can't seem to understand the practice exam solution. Equations and Variable Definitions provided in NCEES handbook: When looking at the question below what i gathered was the following: Givens: E (Illumination)= 50 fc Length of Room= 50...