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Yeah if you log into your account and click on the question mark in the top right corner of your screen you'll find a way to send them a message.

I just sent an email to NCEES and I suggest everyone else do the same:   "Hi, I recently learned that the October PE test for Electrical Power was cancelled and that it will be immediately transitioned to CBT.  Can this please be reconsidered?  Myself and many others have spent hundreds of...

Thanks for the video and spending the time responding to all the questions @Chattaneer PE, It's still tough for me to wrap my head around but it seems like the vast majority of questions I've come across are looking for the actual voltage drop so the Note 2 equation isn't used.  I'll try to make...

Wouldn't X = 0.048 since it's in a PVC conduit?  I think the 0.06 comes from using a steel conduit. R + X for 4 AWG per 1000 ft: 0.31 + 0.048 For 500ft: 0.155 + 0.024 theta = arccos(0.9) = 25.84 degrees V = (20A)( @ 25.84 degrees)*(0.155 + 0.024) V = 3.58 (@ 25.84 degrees)

Thanks @Chattaneer PE, so if I'm understanding this correctly you never use the Note 2 equation for finding conductor impedance but you will use the Note 2 equation when you need to find the voltage drop and you are only given the circuit PF (not voltage or current PF separately)?  Otherwise...

When calculating the effective impedance when we would we use Chapter 9 Table 9 Note 2: Ze = R x PF + XLsin[arccos(PF)] rather than just using the R and XL values from the table in the following formula: Z = (distance) * (R+jXL) Most of my practice problems don't use the Note 2 equation at all...

When a motor is directly connected to generator terminals, does that mean that the motor and generator are parallel?  I would've thought they would be in series.

The solution to this problem calls out to use 210.19(A)(1) to get the total load and then to use 310.15(B) Informational Note No 2 -> Table 310.15(B)(16) -> 240.4(D) Can I instead assume that using 210.20(A) to get the total load and then going straight to Table 240.6(A) to find that the...

@BebeshKing so in general should I not assume that V phase = V Line /sqrt(3)? I should try to prove it each time? Thank you both for the comments!

The solution to this question notes that "Since the source is ungrounded, the phase-to-phase voltage is the line voltage". Does this mean that if there was a neutral you can't assume the phase-to-phase voltage is the line voltage?  I have been treating phase-to-phase voltage as line voltage...