I must be missing something obvious here....
Why does the answer use Z/E(phase) = I? I understand why we use phase voltage and the angles and that we are looking for the magnitude, but why are they dividing the Z by voltage to get current?
Thanks!
This one got me right away as well.... Remember that the peak-to-peak voltage is twice the peak voltage. So you have to divide his given voltage by 2 then convert to RMS.
From wikipedia:
Peak values can be calculated from RMS values from the above formula, which implies Vp = VRMS × √2...
Hi,
Perhaps I am missing something (or perhaps I am dense)...but can someone shed some light on when to divide by the sqrt of three on AC motor problems when the connection type isn't given?
For example in practice problem 3 they say calculate the full load phase current drawn by 440V, 20hp...
I am having a bit of trouble following this example....I am missing something how they are calculating the bases.
Why when the Sbase and Vbase are calculated are they shown as 15MVA and 13.9K? Shouldn't the Sbase be 15/3 and the Vbase be 13.9/sqrt(3) when calculated for a 3-phase system...
Could someone point me to the correct spot in the EERM or the practice problems to review a few poblems like this...I can't seem to find them?
Thanks,
Jason
Hi,
The only thing I could find on the NCEES site was:
PE Electrical and Computer Sample Questions and Solutions Book and CD-ROM
Is this what everyone is referring to as the NCEES practice exam?
Thanks!