BamaBino
Well-known member
This is from sample college test. I disagree this answer but agree with the all the other problems answers.
I see the problem as the load across the secondary being 600 ohms.
The secondary voltage would be 600V and current 1 A.
And the circuit in the primary being 5 Amps, answer B.
Q.33 A 1:5 step-up transformer has 120V across the primary and 600 ohms resistance
across the secondary. Assuming 100% efficiency, the primary current equals
(A) 0.2 Amp. (B) 5 Amps.
© 10 Amps. (D) 20 Amps.
Ans: A
I1= V1 /R1 = 120/600 = 0.2 (n = 100%, losses are zero \V1 = VR = I1R1)
I see the problem as the load across the secondary being 600 ohms.
The secondary voltage would be 600V and current 1 A.
And the circuit in the primary being 5 Amps, answer B.
Q.33 A 1:5 step-up transformer has 120V across the primary and 600 ohms resistance
across the secondary. Assuming 100% efficiency, the primary current equals
(A) 0.2 Amp. (B) 5 Amps.
© 10 Amps. (D) 20 Amps.
Ans: A
I1= V1 /R1 = 120/600 = 0.2 (n = 100%, losses are zero \V1 = VR = I1R1)