Since when is dividing amps by impedance give you amps? The way I did it was to take 1pu (volts) / total Z to get the Ipu. Then multiply that by the Ibase. I just assumed a 1pu volts, I'm not sure that was even correct. But nonetheless, I still don't understand how they got real amps by doing Ibase/Zeq. The only way I see that they would get Ireal = Ibase/Zeq is if they actually did Ibase * (1pu volts/ Zeq) = Ibase/ Zeq and they didn't show all the work.
Last edited by a moderator: