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Any Tips for the "PE Laws and Rules Exam" for those Applying to be a PE in CA? I was fortunate enough to pass the PE exam recently and just submitted by application here in CA. At the end of the application i see we need to take the "PE Laws and Rules Exam"? Is this one of those commonsense...

In the question below we are asked to find the voltage at panel A due to a voltage drop across the conductor Based on Table 9 I did the following: Zeff_ohms= (0.029 *PF + 0.048*sin(Arccos(PF)) ) * 250/1000 = 0.013 ohms So then i simply said VpanelA_LN= VLN_mainPAnel- Vdrop_Cable_LN=...

In the question below we are asked to determine the speed regulation of the induction motor. From what i recall and see in the NCEES handbook confirms that this is done using the following formula: slip=(Ns-N / NS )*100 For some reason the solution uses N instead of Ns as the term in the...

In the question below VAB across the load is given We also know the line current across the conductor In the solution the voltage across the load is divided by root three why is this the case isnt the typical rule of thumb VL=Vphase for a delta configuration?

In the sample NCEES question below we are given the losses at 0% and 50% kVA I realize the 0% losses represent the no load losses which are constant Now the 50% loading value includes both the partial copper and the no load losses so subtracting the no load losses makes sense The part i dont...

For the Question below im having trouble understanding the simplifications made. So far i understand we are given 3P quantities and we are after the ratings of each 1P XFRM that make up the 3P auto XFMR where: 3Ph MVA= 180 Therefore, this means the 1P MVA= 60 Assuming this is an ideal...

Hello, In the sample question from the NCEES PE exam in the solution they consider a 30 Degree Phase shift between Phase to Phase and Phase to ground voltages From what i recall VAB leads Van by 30 deg which is why they place a -30 deg angle on Van However this is the first time i see one of...

Hello, I was looking at the sample PE exam question below. When solving the question i decided to use the XFMR Secondary voltage and MVA as my base values. Which then required the Gen imp to be converted to the XFMR MVA base. When doing so the first time i followed the process below...

In the question below we are given the max demand for 4 different 15 min time periods. We are also told that the max demand at t=0 is 35kW With the given information for the average consumption at time interval 1 from that i understand refers to from t=0 to t=15 min which from the graph is 25...

Hello, In the question below we are after the 3Phase fault current on the secondary of a 12.47/0.480 kV XFMR. Now in addition to the XFMR parameters we are told the "Fault Duty" on of the 12.47kV side of the system. My interpretation is that this represents the equivalent MVAsc of the system...

hello, In the sample question below the drop across the 1-Phase Cable is considered twice. I cant recall why this has to be done can someone please refresh my memory?

I tried looking at the question below and I can't seem to understand the practice exam solution. Equations and Variable Definitions provided in NCEES handbook: When looking at the question below what i gathered was the following: Givens: E (Illumination)= 50 fc Length of Room= 50...