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    Why does this current angle change when solving for sending-end power factor?

    (I think this problem has a typo; 0.8 lagging power factor should be 0.85 lagging.) When the solution starts solving for V_S, the sending-end voltage, 5.11 degrees is subtracted from the current angle. Is that the angle from V_R, the receiving-end voltage? If so, how do you solve for that angle?
  2. N

    NCEES Power Practice Problem #524

    (Practice exam book printed in 2014) Can someone tell me where the multiplication factor of 4 comes from when calculating the 100% rated load loss? And where that line of calculation even comes from? Also, with the given information, are the I^2*R losses calculated the following way...
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