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  1. S

    Graffeo Ex 14

    you forget conjugate of current S=VI*=(IZ)I*=(9.4∠-38.7°)(1+j3+10+j8) (9.4∠+38.7°)=(9.4∠-38.7°)(11*1.414∠45°) (9.4∠+38.7°)=1374.56∠45°=971+j971
  2. S

    The Electrical Engineer's Guide to Passing the Power PE Exam Spiral-bound – 2016 review

    did anyone use this book? compared to NCEES material, which is better? The Electrical Engineer's Guide to Passing the Power PE Exam Spiral-bound – 2016 https://www.amazon.com/Electrical-Engineers-Guide-Passing-Power/dp/0988187612
  3. S

    Transmission Line and Voltage drop issue

    Transmission line Sending End of Receiving end formula is VS=VR+I*(R+jX), VR and VS shall be line-neutral If VR and VS is line-line, shall use VS=VR+(1.732)*(I)*(R+jX) which is quite similar to voltage drop calculation, right? VDLN=I*(RCos θ+XSinθ) VDLL=1.732*I*(RCos θ+XSinθ)
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