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  1. J

    Any body here in the Energy/Gas/Oil business?

    I am a consulting engineer for a firm that does MEP design (Mechanical, Electrical, and Plumbing) for construction projects. I am really happy where I am at, but I have been advised by a mentor to check out what is available in the local oil and gas type companies such as Sandridge, Chesapeake...
  2. J

    What a relief

    It sure is nice to have the test behind me for awhile. I can't wait for the results to come back. I'm confident that i passed, but that doesn't make me any less anxious. How did everyone else feel like they did?
  3. J

    Complex Imaginary Volume 3, Problem #68

    I have a question regarding a given solution. Given the following parameters, can you show me the work to find the transformer's efficiency? Given Tx: 20kVA 6.6/2.8 kV Core Loss = 75 W Copper Loss = 241 W Is = 6.6<-22 A , where Is = secondary current The formula I would use is: Eff =...
  4. J

    Complex Imaginary Volume 2 #36

    This problem involves computing the power output of a 3-phase induction generator which is connected to a wye system. You are given the full load output of 325A and the generator nameplate rating of 2.4 kV. My thought was that the apparent power should be calculated as such: (1) S=Vp*I*sqrt(3)...
  5. J

    NCEES #111

    For the NCEES power sample question #111 I have seen several discussions, but none of them outlined the KVL method in detail for finding the answer. I understand the solution was given by converting to a delta to simplify some math, but that's not the way my brain works. To me, the KVL is the...
  6. J

    NCEES #513

    Has anybody else worked #513 without using per-unit analysis? I've searched the forum for examples without any luck. The per-unit solution in the NCEES book does not help me at all. I worked it without the PU conversion and came up with an answer of 418A (the answer given is 415A). My solution...
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