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  1. S

    MA PE Results Are In !

    Did anyone contact PCS for further instructions on how to obtain license ? Result notification said we should get an email with instructions but I did not get any as of today. Please share if you did. Thanks
  2. S

    Must have Book for PE Power !

    I did not refer to Mike Holt's forum for NEC codes. I guess 1200 questions sounds too much. I started my prep late (around first week of September) and did not enough time to explore the online resources. So I have no basis to compare this book to Mike's forum or any other code related...
  3. S

    Must have Book for PE Power !

    I moved my post to the below sub-forum, which is much appropriate for this kind of post. />http://engineerboards.com/index.php?showtopic=20657
  4. S

    Must have Book for PE Power !

    I have seen so many posts here discussing various books which one should have to prepare for PE Power but none of the posts discusses the book which I will mention below. I took this test in October for the first time and passed it quite comfortably. After reading many threads here I went to...
  5. S

    MA PE Results ... not yet ...

    Practo, Unfortunately "NO". I asked PCS about it but they say the board's policy is to not release scores. I am sure NCEES releases full scores to the board. So curiosity aside, have couple of more drinks in the name of "December Special" and relax.
  6. S

    MA PE Results ... not yet ...

    After posting in this thread, this is what I found http://engineerboards.com/index.php?showtopic=19234 . Looks like they got letters in the mail but PCS note on results says they will send email this time.
  7. S

    MA PE Results ... not yet ...

    So now we have the results, how long we need to wait before we can get our license numbers? My result notification says I will get an email from PCS within 15 business days. Is there more paperwork involved ? Any input's would be greatly appreciated. Thank you.
  8. S

    Map: October 2012 Exam Results

    So Orange for MA and VA... 52 days of waiting after the test and 3 days after the NCEES released the results.
  9. S

    OFFICIAL Oct '12 PASSING THREAD (banner)

    Soma - passed PE MA - Power
  10. S

    MA PE Results Are In !

    Congrats ! Excuse my spelling in above post...should have been "Fellow MA PE mates"...got little excited.
  11. S

    MA PE Results Are In !

    Hello Fello MA mates..results are in. Passed PE Power first attempt !
  12. S

    NCEES Problem 109

    The system is grounded even now. Well, instead of grounding phase A on supply side ( grounding "A" of supply will keep the grounds at same potential), if point "N" is grounded, then it creates a short circuit on phase A of of the supply. Also, the phase to ground currents of other two phases...
  13. S

    NCEES Problem 109

    I do not think there would be any difference. Since this questions is bought up, I will post various phase to ground voltages I calculated for this system. Vag = 0, Vbg= 13.2 @ 180 deg and Vcg = 13.2 @120 deg. As we can see, this method of grounding creates unequal phase to ground voltages...
  14. S

    NCEES 510, 537 & 540

    Thanks Dean !
  15. S

    Kaplan Afternoon #14 question

    You are right, the new load angle would be 28.26. The reactive power supplied will be around 2.8 KVAR.
  16. S

    NCEES #111

    Dean, NCEES method would have been correct if the load was 3-phase, 4 wire, Y-connected. In delta connection phase and line voltages do not have 30 deg. shift. I agree with you that in y connection there is a phase shift of 30 deg between line and phase voltages. Soma Soma
  17. S

    NCEES #111

    As Katag did, loop analysis can also be done but since this is a balanced system we can skip an extra piece of calculation of drop in line bB.
  18. S

    NCEES #111

    This is the alternate way I posted above Vab = VAB + IaA * Z line two times impedance for calculating voltage drop should be only used for single-phase two-wire circuits.
  19. S

    NCEES #111

    It's a delta connected load, so voltages do not shift nor do they change magnitude. Just use Vab = VAB + IaA * Z line. Though the answer is correct, the method used in the solution is wrong.
  20. S

    NCEES #518

    Each diode conducts for 60 deg, so the min value of output voltage is VmSin60 => Vm*0.866 = 1.225 and Max is VmSin90 = Vm.
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