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I have a Mark's Standard Handbook for Mechanical Engineers, 10th edition for sale. $75 (=$70 + $5 shipping). The book is in great condition, but I do not have the dust jacket. I used this book for the ME Machine Design exam last April. Send me an e-mail if you are interested. I would like to...

I have one that I am willing to part with. Send me an e-mail, and we can figure out the details. [email protected]

Congratulations everyone!!! I have a huge smile too. ME machine design..........now I am a Gigantic DoucheBag

I took the ME Machine Design in April, and I felt the MERM was sufficient for the morning; however, I highly recommend the NCEES practice exam also. I had a few other books including Shigley's, which I referenced in the morning session, primarily because I knew exactly where I had to look. I am...

Thanks! I do have a sheet from the MI board that says "candidates may take any reference material into the test room; however, all material must be bound". I assume this covers my question. Regardless, I will try to call the MI board.

By now we have worked hundreds of problems, and have either binders or notebooks full of completed practice problems. Are the solutions to practice problems allowed in the exam room as a reference? I haven't been able to find anything that explicitly says yes or no. How about the NCEES practice...

I think a few of us agree with you. Here is a link to an earlier thread. http://engineerboards.com/index.php?showtopic=11828

This problem has a square bar with two torque loads axially along the bar. I believe the problem can be solved by two methods. 1) Superposition where the length of the bar is measured from the wall, and the torque loads are evaluated individually. 2) Or by using a torque diagram, where the bar...

Thanks!! That is the answer I was looking for.

When using f = 1/(2pi) * (g/delta)^1/2 to solve for a rotating shaft's critical frequency you can use beam equations to solve for the static deflection (delta). Is the static deflection calculated for the location of the weight or the maximum deflection of the beam? I am specifically referring...

After looking it over several times I getting the same resultant shear of 3788 psi. It may be a case where I have looked at this problem for so long the mistake is staring me in the face, but I just can't see it. None the less, here are my numbers... Torsional shear x-component = 3348*cos(39.8)...

I'll take a look at the critical fastener problem again, but...Yes, the very next problem calculates the areas wrong.

I believe the final number is correct...I got shear = 3790 psi, however, I see the mistake you are referring to. The solution uses the sine of theta to calculate the horizontal component. Obviously it should be cosine of theta. I agree that this is a mistake. Here is the kicker though...punch in...

I agree as well. I solved this problem yesterday, and was disappointed with the method the manual used to get an answer. An energy balance should solve the problem once the initial velocity is calculated. I am also getting more and more frustrated with the 6MS machine design book the deeper I...

The problem is as follows... In a cyclic operation, an A313 stainless steel wire helical spring has an outside diameter of 0.5 inch and a wire diameter of 0.08 inch with 30 active coils. The critical frequency is most nearly...? The MERM gives a straight fwd equation (eq. 52.19) for the...

The only place I have been able to find that equation is in Mark's Handbook. Given are only two equations and each is based on the units desired. (1) mils/yr = 534W/DAT (2) micro-m/yr = 87,600W/DAT Where: W = weight loss [mg] D = density [g/cm^3] A = area [sq. inch or sq. cm] T =...

Regarding the failure theories and alternating stress question... For ductile materials (elongation >5%) use max shear stress or von Mises (distortion energy) criterion. Max shear stress theory is more conservative than von Mises, but von Mises has better correlation with test data. For...

To solve this problem you must calculate the torsional deflection of a square steel bar. The problem is solved using superposition, which I understand. However, when solving for the torsional deflection due to the bar/load farthest away from the wall, a length of L = 12 inch is used in the...

I have found the error of my way Chris. The 6MS answer is definitely wrong. I am happy to see that proper IC technique and Mark's match up. In the end, I got ~ 6 ft/s (73 in/s) for the slider velocity.

Thanks Chris. I will have to spend some more time reviewing slider-cranks. I was able to find a simple calculator on-line that gave a result that matched Mark's equation. This makes me believe you are correct about the mistake in 6MS. Now I just have understand the details of my mistake. Do you...