Recent content by Raiden

I am selling my CI book (Volumes 1-4 -Complete Set (120 USD)). I also have the Power Practice Problems (50 USD) and the Electrical Enginnering Sample Examinations from John A. Camara ( 120USD) and the Power Reference Manual by J. A. Camara (120 USD). If you buy all (4) I will also put in...

Passed, Power in Alabama

Josh has posted this "Errata" on the website. I have found some other issues that I feel that are errors on the 2012 version. CI Test #2 Problem 10 Answer: VP = 40 * [0.34 cos (-10) + 0.023 Sin (-10)] = 13.2V then (13.2V/120) * 100 = 11.0% CI Test #1 Problem 48 Answer: V(d) = I *...

Wael, I see your line of reasoning but take into account that the load voltage at 3.3KV would include the cable all the way back to the source. This also means that V source = IZ (from the cable all the way to the load) + V load (which includes the load and the cable connecting the load back...

The problem speaks about a transformer connected to the utilitiy at a 6.6kv and the source impedance (utilitie's) is 0.94%. If the transformer rated impedance is 4.25% and rated current is 1720A. (Secondary voltage is 480V) What is the short circuit current available at the transformer...

i am looking at my CI version of the book and tthe answer shows + instead of the - you mentioned. Maybe you have an older version.

This is torture!!! AAAAAAAAAAHHHHHH!!!!! Almost everyone in the office have asked if the results are in!!

I did took the PE Power too and I think it was not as demanding as I expected it to be. One mental note in case I have to do it again,...make sure you know the concepts (not just the formulas).