Recent content by cconnawa

I1 = Zeq/Z1 * I-load is exactly equal to I1 = Z2/(Z1+Z2) * I-load because in Chelapati's formula, Zeq equals the equivalent Z of the two transformers in parallel. I.E., Zeq = Z1*Z2/(Z1+Z2) If you divide Zeq/Z1 based on that definition, you get Z2/(Z1+Z2). So how did you get a wrong answer...

You can do it that way, and you will still get the same answer. It's just another step you don't need which can potentially be an error while you are performing the calculations. There are certain instances for which the -30 phase shift from line-line to line-phase is really important, for...

The magnitude is the same no matter what is the initial reference angle, so long as Phase A is 120 degrees in front of Phase B. It doesn't matter if Phase A is 0, -30, or -10, for that matter... as long as Phase B is 120 degrees behind it, i.e., balanced. Do the math and try it. Plug in...

As reminder to all of us: Capacitors don't draw KVAR's, they supply them... so the system total KVAR will be the motor 3-phase KVAR minus the Capacitor 3-phase KVAR. Notice how the Capicitor KVAR is given in per phase... this requires conversion first to 3-phase KVAR to match the motor, or...

Yes, it should be j0.05. If you do the math, you'll see the answer is correct (1/(.15+.15+.05) = 2.857 which is what he shows there.

What you are missing is that you are mixing up phase voltages with voltages at certain locations. The voltage at location A is V_A, not Va. The problem states that at point A, the line to line voltage (V_A) is 500kV with angle "sigma". It goes on to say that at location B (some distance away...