Recent content by Benee

I pass PE in Texas. :party-smiley-048:

I'm in Texas, I pass

Thank you everyone ! and Good luck

Thanks Jim, your statement is true, Final equation is the same but I think in order to derive the final equations, the method is diffrence. I try to figure it out how to come up with the final equation but don’t know how to do it yet. Of course for the PE exam, I just accept the fact and use it

Since you're very knowledgeable, Let me ask this question, IF the problem state that the Transmission lines were connected from the Delta source, then what Voltage do you use and why ? Can you explain, Master ?

Well, You're not the only one that have that thought. So don't feel bad.

Can you post the problem and solution ? Since I don't have this book thanks

Thank you very much

Thank you very much, The key world is "directly Proportional". Without your help, I will bang my head to the wall :party-smiley-048: :party-smiley-048:

Is there any one having a problem for # 537? The math part and the solution don't agree to each other. Per the Capacitance of the transmission line equation. If Rc increase, then the Capacitance will get larger. However the solution state " if Rc increase, the Capacitance of the Transmission...

This is what I got but the solution is not match with any choice in the solution Vnc = VnB + VBC Vnc = (12.25 <75)* (-10j) + 173.2<-90) = 236.62<-60

Yes, you can do either way and you will get the same answer, by the way, the solution is have an error, The current Iab is 12.247<75 instead 1.2247<75.

I worked it out and I have the VnC is 236.62<-60 Volt. which is not match to none of the choice in the question. Can you post the solution ?

What PE exam did you take ?

Can you show me some of the thread about Illumination ?