Architectural Engineer need help with pump question
Posted 24 March 2012 - 08:50 PM
Q: A 6" pump operating at 1800 rpm discharges 1800 gpm of cold water (S.G. = 1) against an 80 foot head at 60% efficiency. A dynamically similar 8" pump operating at 1170 rpm is considered as a replacement. The total head that can be expected from the new pump is most nearly what?
A: 60.09 ft
In the solutions they show the work, but don't explain why they did what they did: head = (8/6 * 1170/1800)^2 * 80 = 60.09
It looks like they just did proportions? What is the base equation they started with?
Posted 25 March 2012 - 10:27 PM
Darcy is H = F*(L/D)*(V^2/(2g))
I think it is safe to assume since they said the second pump is a replacement that vertical component of the total head is irrelevant. I would assume this is a friction head loss question.
I might be wrong though ... Let me sleep on this one.
Posted 26 March 2012 - 03:11 PM
"The performance of one pump can be used to predict the performance of a dynamically similar (homologous) pump. This can be done by using Eqs. 18.48 through 18.53."
The first equation, 18.48, Is where the work they show comes from.
n1, D1, h1, n2, D2 are knowns, solve for h2
Edit: Sorry, forgot to reference this is from the MERM, ch. 18-25. Also, Example prob. 18.11 is almost the same situation.
Edited by pbrme, 26 March 2012 - 03:14 PM.
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