Posted Thursday at 11:37 PM The solution for problem #536 begins by having us use the formula: µ' = µ(sin(Φ/2)) ÷ (Φ+ sinΦ) They help us by making sure we know to convert the angle of 80° to radians, 80° = 1.4rad But when I put that into the equation, I don't get the same answer the book gets (book has 0.864, I get 0.00686). Am I doing it wrong or is the book wrong? I've been wanting to ask this since January but I feel like it's a silly question so I never asked. It's time to hide the pride and get the help I've been looking for. Share this post Link to post Share on other sites

Posted Friday at 12:27 AM Well, 80 degrees is 1.39626 radians. Without knowing the problem I can't help you much more than that. Share this post Link to post Share on other sites

Posted Friday at 01:03 AM Make sure your calculator is in radian mode. Share this post Link to post Share on other sites

Posted Friday at 01:08 AM Also the equation is wrong and it should be u×(4×sin (phi/2)/(phi+sin (phi)) You are missing a 4 (so is NCEES, but it is a typo) see the MERM page 54-20, equation 54.95 in the 13th edition. The numerical value of .864 is right of you use the right equation and have your calculator in the right mode. Share this post Link to post Share on other sites

Posted Friday at 01:28 AM 9 minutes ago, MEC_SBU said: Also the equation is wrong and it should be u×(4×sin (phi/2)/(phi+sin (phi)) You are missing a 4 (so is NCEES, but it is a typo) see the MERM page 54-20, equation 54.95 in the 13th edition. The numerical value of .864 is right of you use the right equation and have your calculator in the right mode. MEC, Thank you!! Also, thank you for the reminder about setting my Calc to Rad instead of Deg. Share this post Link to post Share on other sites

Posted Friday at 02:01 AM No problem, you're welcome. The calculator/radians thing you gotta be careful with. Don't want to live this meme! I am heading to bed (on the east coast). Good luck tomorrow! I hope we both pass! Share this post Link to post Share on other sites