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terzaghi83

Direct Shear Testing?

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terzaghi83    3

Just to confirm:

I've looked through a couple different examples and they all say the following:

When given a normal force and a shear force, divide each one by the same area of the sample (Pi*d^2 / 4 for a circular direct shear sample) to get the appropriate shear stress and normal stress.

Is this correct? It sure seems like I should divide the normal force by Pi*d^2 / 4, but the shear force by something else.

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