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NCEES 2008 #114

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jco0518    0

I have trouble solving this problem. Please see the attached question and help me understand the answer. Thanks.

Find the Deflection I=71'24'-65'48'=5'36'

deflection from PI to center would be I/2=5'36'/2=2'48'

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This is a pretty simple question and typical on the exam. I suggest drawing it on paper and understand the resulting angles between two lines with known bearings. These is a common scenario where 2 of the 3 parameters are provided and you would need to solve the 3rd. For example, they can ask you to solve the bearing of a line based on the bearing of the other line and the deflection angle between the two. It's nothing but geometery and you need to master it for the exam.

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